How this works
Current flows out on one conductor and back on the other, so the drop is across both. The calculator multiplies the one-way length by two for you.
Voltage drop = 2 × length × resistance per unit length × current Voltage at device = supply voltage − voltage drop
Resistance comes from NEC Chapter 9, Table 8: DC resistance of uncoated copper at 75 °C, in ohms per 1,000 ft, solid or stranded. Table 8 stops at 18 AWG. For 22 and 24 AWG, common in access control and alarm cable, the calculator uses NBS Handbook 100, the copper wire tables Table 8 is itself calculated from: 19.7 and 31.2 Ω per 1,000 ft at 75 °C. Metric sizes use IEC 60228 (class 2 stranded copper, maximum resistance at 20 °C), corrected to the chosen temperature.
Amps or watts
Enter amps when the datasheet gives a current, as it usually does for locks, strikes and sirens. Enter watts for devices with a switching power supply, such as most IP cameras and many readers and heaters. Those draw more current as their input voltage falls. The calculator solves for that, so a watt-rated load drops more than the same load treated as a fixed current. If the run cannot deliver the power at all, it says so rather than giving a number.
Pass or fail
Enter the device's minimum operating voltage from its datasheet. Typical wording is "12 VDC ±15%", which means a minimum of 10.2 V. The calculator then gives a pass or fail, the longest run that still passes on this wire, and the smallest wire size that passes on this run.
What this does not account for
- Loads spread along a run, such as several devices daisy-chained. The calculator puts the whole load at the far end, which overstates the drop and so errs on the safe side.
- AC reactance and power factor. For 24 V AC at these wire sizes, resistance dominates, but this is a DC resistance calculation.
- Copper-clad aluminium (CCA) cable. Its resistance is higher than copper's, so this calculation would understate the drop.
- Connector and terminal resistance, and a supply that sags under load. Measure at the device when it matters.
Common questions
- What percentage drop is acceptable?
- The device decides, not a percentage. The NEC's 3% and 5% figures are informational notes for branch circuits and feeders, not rules for low-voltage wiring. A 12 V lock that works down to 10.2 V can tolerate a 15% drop; a device with a narrow input range cannot. That is why this calculator asks for the device minimum.
- Why does the length count twice?
- Because the current goes out and comes back. A 100 ft run is 200 ft of conductor.
- Should I use 24 V instead of 12 V?
- For the same power, doubling the voltage halves the current, so the drop is a quarter as large in proportion. When a device accepts either voltage, a long run is usually easier at 24 V.
- Does doubling up conductors help?
- Yes. Two conductors in parallel on each leg halve the resistance. Set "Conductors per leg" under the temperature options.
Sources
- NFPA 70, National Electrical Code, Chapter 9, Table 8, Conductor Properties. DC resistance at 75 °C, uncoated copper, Ω/kft, and Note 2's temperature formula with α = 0.00323. Values checked against the 2017 and 2011 editions.
- NBS Handbook 100, Copper Wire Tables (1966), Table 6: 22 and 24 AWG at 75 °C.
- IEC 60228, Conductors of insulated cables: class 2 plain copper, maximum resistance at 20 °C (Table 2 in the 2004 edition, Table 4 in 2023).
Every source used on this site, and how each number is used.